1. Introduction
In the management entrance tests, questions from quadrilaterals are conceptually more advanced than those pertaining to polygons of 5 or more finite sides. Accordingly this lesson covers concepts pertaining to quadrilaterals in detail and the basic properties of other polygons with 5 or more finite sides.
A polygon is a shape enclosed by 3 or more intersecting lines. A triangle is a polygon with 3 sides. We covered triangles in the previous lesson. We will start this lesson with the basic properties that apply to all polygons, the concept of regular polygons and then learn about quadrilaterals.
2. Basics of Polygons
An n-sided polygon will be bound by n intersecting lines with n vertices, n edges and n interior (and n exterior) angles. In the 5-sided polygon (pentagon) shown below, the
(a) 5 vertices are A, B, C, D and E
(b) 5 edges are the line segments AB, BC, CD, DE and EA.
(c) 5 interior angles are ∠1, ∠2, ∠3, ∠4 and ∠5.
(d) 5 exterior angles are ∠6, ∠7, ∠8, ∠9 and ∠10.
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2.1 Properties of Polygons
In an n-sided polygon (where
n > 3), from any vertex, we can draw diagonals to all vertices other than itself and its two adjacent vertices. So, from 1 vertex we can draw (n−3) diagonals.
(n−3) cuts will divide a polygon into (n−2) triangles. So, sum of interior angles is the sum of angles of the (n−2) triangles formed.
∴ Property 1: Sum of interior angles of an n-sided polygon =(n−2)×180o
Example 1
What is the sum of interior angles of the pentagon ABCDE?
Solution
The 2 diagonals from A are AC and AD
This forms 3 triangles – △ ABC , △ ACD and △ ADE
Sum of interior angles of ABCDE = Sum of interior angles of △ ABC , △ ACD and △ ADE
=180o+180o+180o =3×180o
=540o
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Answer:
540o
If each side is extended in 1-direction across vertices, exterior angles are formed. At each vertex, we have a linear pair (sum of angles is
180o) comprising of 1 interior angle and 1 exterior angle.
Sum of exterior angles = Sum of linear pairs - Sum of interior angles
=n×180o−(n−2)×180o
= 180o(n−n+2)
= 360o
∴ Property 2: Sum of exterior angles of an n-sided polygon = 360o
Example 2
What is the sum of exterior angles of a pentagon?
Solution
At each vertex, the two angles marked form a linear pair. For instance, ∠1+∠6=180o
Sum of the 5 linear pairs =∠1+∠2+⋯+∠10=5×180o
Sum of Interior angles =∠1+∠2+⋯+∠5=3×180o
Subtracting the 2 equations above,
Sum of Exterior angles =∠6+∠7+⋯+∠10=2×180o=360o
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OR, directly applying the
formula in Property 2,
sum of exterior angles
=360o
Answer: 360o
Diagonals are lines that connect any 2 vertices of the polygon, that are not adjacent to each other.
(
Note:
Triangle is the only polygon with 0 diagonals, as all vertices are adjacent to each other.)
As explained at the start of this page, from any 1 vertex we can draw (
n - 3) diagonals.
From n vertices we can draw n(n−3) diagonals. But, we are counting each diagonal twice. (e.g., AC and CA are counted as 2 different diagonals).
∴ Property 3: Number of diagonals in an n-sided polygon = 2n(n−3)
Example 3
What is the number of diagonals in a pentagon?
Solution
In this figure, 2 diagonals can be drawn from each of the 5 vertices.
As these are double counted,
Number of diagonals =22×5=5
Directly applying the formula in Property 3,
Number of diagonals =25(5−3)=5
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Answer:
5