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CAT 2022 Slot 3 QA Q11 — The minimum possible value of $\dfrac{x^2 - 6x + 10}{3 - x}$, for $x < 3$, is | Mockat | Mockat
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Question 11
CAT 2022
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Q 11 / 22
Q11
CAT 2022 Slot 3 QA
The minimum possible value of
x
2
−
6
x
+
10
3
−
x
\dfrac{x^2 - 6x + 10}{3 - x}
3
−
x
x
2
−
6
x
+
10
, for
x
<
3
x < 3
x
<
3
, is
1
2
2
1
2
\dfrac{1}{2}
2
1
3
−
1
2
-\dfrac{1}{2}
−
2
1
4
-2
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