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Data Interpretation

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Data Tables

Data Tables

MODULES

Introduction
Cases 2 & 3
Case 4
Case 5
Case 6

PRACTICE

Data Tables : Level 1
Data Tables : Level 2
Data Tables : Level 3
ALL MODULES

CAT 2025 Lesson : Data Tables - Cases 2 & 3

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Example Case 2

Answer questions 5 to 7 based on the following information::

Spam that enters our electronic mailboxes can be classified under several spam heads. The following table shows the distribution of such spam worldwide over time. The total number of spam emails received during December 2002 was larger than the number received in June 2003. The total number of spam emails received during September 2002 was larger than the number received in March 2003. The figures in the table represent the percentage of all spam emails received during that period, falling into those respective categories.


[CAT 2003L]

5) In which category was the percentage of spam emails increasing but at a decreasing rate?

(1) Financial
(2) Scams
(3) Products
(4) None of these

6) In the health category, the number of spam emails received in December 2002 as compared to June 2003

(1) Was larger
(2) Was smaller
(3) Was equal
(4) Cannot be determined

7) In the financial category, the number of spam emails received in September 2002 as compared to March 2003

(1) Was larger
(2) Was smaller
(3) Was equal
(4) Cannot be determined

Solution

5)

In case of scams, the percentage of spam emails decreased in June 2003 from March 2003. So Scams can be eliminated.

In case of financial,



As percentage of spam emails in financial is increasing at an increasing rate, but the condition is given as it should increase at decreasing rate. So financial can be eliminated.

In case of products,


The category in which the percentage of spam emails is increasing but at a decreasing rate is products.
Answer: (3) Products

6)

The total number of emails in Dec 2002 was greater than the total number of emails in June 2003.

Therefore, 19% of the total number of emails in Dec 2002 is greater than 18% of the total number of emails in June 2003.

So, the total number of spam emails in the health category was larger in December 2002 as compared to June 2003.

Answer: (1) Was larger

7)

It cannot be determined. Though the percentage of spam emails in the financial category is lower in September 2002 as compared to March 2003, the total number of spam emails in September 2002 was higher as compared to March 2003.
Therefore, we cannot say that for which month and year out of these two, the number of spam emails in the financial category was larger or smaller.

Answer: (4) Cannot be determined

Answer:
5) (3) Products
6) (1) Was larger
7) (4) Cannot be determined

Example Case 3

Answer questions 8 to 9 based on the following information::

An industry comprises four firms (A, B, C, and D). Financial details of these firms and of the industry as a whole for a particular year are given below. Profitability of a firm is defined as profit as a percentage of sales.


[CAT 2003L]

8) Which firm has the highest profitability?

(1) A
(2) B
(3) C
(4) D

9) If firm A acquires firm B, approximately what percentage of the total market (total sales) will they corner together?

(1) 55%
(2) 45%
(3) 35%
(4) 50%

Solution

8)

Profitability%Profitability \%Profitability% = profitsales×100%\dfrac{profit}{sales} \times 100 \%salesprofit​×100%

ProfitabilityofA=491424568Profitability of A = \dfrac{4914}{24568}ProfitabilityofA=245684914​ ≈ 500025000=15=20%\dfrac{5000}{25000} = \dfrac{1}{5} = 20 \%250005000​=51​=20%

ProfitabilityofB=407525468Profitability of B = \dfrac{4075}{25468}ProfitabilityofB=254684075​ ≈ 400025000=425=16%\dfrac{4000}{25000} = \dfrac{4}{25} = 16 \%250004000​=254​=16%

ProfitabilityofC=475023752Profitability of C = \dfrac{4750}{23752}ProfitabilityofC=237524750​ ≈ 500025000=15=20%\dfrac{5000}{25000} = \dfrac{1}{5} = 20 \%250005000​=51​=20%

ProfitabilityofD=394615782Profitability of D = \dfrac{3946}{15782}ProfitabilityofD=157823946​ ≈ 400016000=14=25%\dfrac{4000}{16000} = \dfrac{1}{4} = 25 \%160004000​=41​=25%

Answer: (4) D

9)

Total sales of A and B combined will be, Rs.50,036.

Total Sales = Rs.89570.

(A+B)SalesTotal Sales=5003689570\dfrac{(A+B) Sales}{Total \ Sales} = \dfrac{50036}{89570} Total Sales(A+B)Sales​=8957050036​ ≈ 5090×100%=55.56%\dfrac{50}{90} \times 100 \% = 55.56 \%9050​×100%=55.56%

Answer: (1) 55%

Answer:
8) (4) D
9) (1) 55%

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