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CAT 2025 Lesson : Percentages - Of Concept & The Denominator

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4. Basic Concepts

4.1 The Of Concept

In percentages, the word of, typically, signifies multiplication.

For example,
40%40\% of 80=40100×80=3280 = \dfrac{40}{100} \times 80 = 32

The above concept applies when used in a statement and not a question (as shown in example 5).

4.2 Expressing numbers as a percentage of total

To express one quantity as a percentage of another, both quantities should be expressed in the same unit.

Example 6

What percent is 2100 grams of 7070 kg?

Solution

To get an equation, we rewrite the above question as a statement, where the units are the same.

As 1 kg = 1000 grams, the statement here is '2.12.1 kg is ____%\% of 7070 kg'.

In this statement, is signifies equal to and of signifies multiplication. Writing this as equation,

2.1=x%2.1 = x\% of 7070

2.1=x100×702.1 = \dfrac{x}{100} \times 70

x=3x = 3

\therefore 2.12.1kg is 3% of 7070kg.

Alternatively

The question simply means if 70 kg were 100%, then what is 2.1 kg in percentage terms.

x=2.170×x = \dfrac{2.1}{70} \times 100% = 3%

Answer:
3%3\%

Example 7

After working for 2424 hours on a project, Elda realised that 25%25\% of the work still remained. How many more hours will she require to complete the work?

Solution

This question can be solved only if we assume that Elda works at a constant rate. CAT and other tests do not test us with riddles. Therefore, you need to make such assumptions, unless explicitly stated otherwise.

Portion of work completed in 2424 hours = 100%25%=75%100\% - 25\% = 75\%

As Elda works at a constant rate, the statement here is, '
2424 hours is 75%75\% of ____ hours'

24=75100×x24 = \dfrac{75}{100} \times x

x=32x = 32

\therefore Additional hours taken by Elda = 3224=32 - 24 = 8 hours

Answer:
88 hours

4.3 The Denominator

What goes into the denominator while calculating percentages is important to understand.

The variable with which a comparison or relation is made will be in the denominator. In most cases, this variable is after than or of in the statement that we form.

For instance, let's say Cleo and John scored
4040 and 5050 marks respectively. If the question is 'By what %\% is John's mark more than that of Cleo?', we can rewrite the statement as 'John's mark is ____%\% more than that of Cleo's mark'.

Clearly, we are required to find the increase in relation to or relative to Cleo's mark.

John has scored
1010 marks more than Cleo. As a percentage this is,

1040×100%=25%\dfrac{10}{40} \times 100\% = 25\%

The statement can now be written as John's mark is 25% more than that of Cleo's mark.

Example 8

Express 22 hours 4040 minutes as the percentage of 11 hour 3636 minutes.

Solution

22 hours 4040 minutes = 2×60+40=1602 \times 60 + 40 = 160 minutes

11 hour 3636 minutes = 1×60+36=961\times 60 + 36 = 96 minutes

The statement here is '
160160 minutes is ___%\% of 9696 minutes'

The answer is
16096×100%=10006%=166.67%\dfrac{160}{96} \times 100\% = \dfrac{1000}{6}\% = 166.67\%

Answer:
166.67%166.67\%

In certain cases, the denominator is implied. When a value of a certain item/variable has changed to another item/variable, then the percentage change is computed in relation to the earlier value, which will be the denominator.

In questions involving years, the value of an item in an earlier year will be the denominator, unless specified otherwise.

Example 8

Express 22 hours 4040 minutes as the percentage of 11 hour 3636 minutes.

Solution

22 hours 4040 minutes = 2×60+40=1602 \times 60 + 40 = 160 minutes

11 hour 3636 minutes = 1×60+36=961\times 60 + 36 = 96 minutes

The statement here is '
160160 minutes is ___%\% of 9696 minutes'

The answer is
16096×100%=10006%=166.67%\dfrac{160}{96} \times 100\% = \dfrac{1000}{6}\% = 166.67\%

Answer:
166.67%166.67\%

In certain cases, the denominator is implied. When a value of a certain item/variable has changed to another item/variable, then the percentage change is computed in relation to the earlier value, which will be the denominator.

In questions involving years, the value of an item in an earlier year will be the denominator, unless specified otherwise.

Example 9

In a farm, wheat production in 20182018 was 150150 tonnes and 20192019 was 165165 tonnes. By what percentage did the wheat production increase in 20192019?

Solution

Increase was 1515 tonnes over the 20182018 production of 150150 tonnes. Therefore, it is implied and understood that the percentage increase is asked relative to the production in 20182018.

Note that it does not make sense to look at an increase in relation to the final value. In this question, it is also implied that we are required to find the annual percentage increase.

%\% increase in 20192019 = 15150×100%=10%\dfrac{15}{150} \times 100\% = 10\%

Answer:
10%10\%

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