calendarBack
Quant

/

Arithmetic I

/

Profit & Loss
ALL MODULES

CAT 2025 Lesson : Profit & Loss - Marked Price

bookmarked

4. Marked Price and Discount

Going forward, CP, SP and MP represent Cost Price, Selling Price and Marked Price respectively.

For some products, such as clothing and electronics, discounts or discount sales are a norm. This means the sellers offer a discount over the stated price to arrive at the actual selling price. This stated price is called Marked Price (MP) . This is the price of a product stated by the seller before any discount.

List Price (LP) is a price determined by the manufacturer, and typically marked on the product, as the price at which retailers have to sell the products. Maximum Retail Price or MRP stated in the packages of fast moving consumer goods, such as soaps, detergents, beverages, etc. are examples of List Prices. These are printed on the packages by the manufacturer. In entrance tests, however, List Price and Marked Price are used interchangeably. So, whatever applies for MP, applies for LP as well.

Let's understand the concept of Marked Price and Discount with the following example.

A trader buys pens at Rs.
100\bm{100} per pen, which is the CP. To make it attractive for customers, she wants to offer a discount.

Therefore, she first marks up the price by 50%\bm{50\%}. At this moment, only the CP is known to the trader. Therefore, the mark-up %\% is applied on the CP.

Marked Price (MP)
== CP + 50 %\% of CP =100+50== 100 + 50 = Rs. 150150

This MP of Rs.
150150 per pen is displayed as the price to customers. The trader then offers a discount of 20%\bm{20\%}. The trader cannot and will not inform her CP to the customer. Therefore, the discount %\% will be applied on the MP, which the customer is aware of. This discount when subtracted from the MP, will give the Selling Price (SP), which is the value for which the pen is actually sold.

Selling Price (SP)
== MP 20%- 20 \% of MP =15030== 150 - 30 = Rs. 120120

To summarise, the two legs in Marked Price & Discount are as follows.
1) MP = CP + Mark-up Value
⇒ MP
== CP + Mark-up %\% of CP
MP
== CP (1\bm{1} + Mark-up %) \longrightarrow (11)

2) SP = MP - Discount
⇒ SP
== MP - Discount %\% of MP
SP = MP (
1\bm{1} – Discount %) \longrightarrow (22)

3) Substituting equation (
11) in (22), we get
SP = CP (
1\bm{1} + Mark up %) (1\bm{1} - Discount %)

Also note the following.
1) Profit/Loss % is a percentage of CP.
2) Mark-up % is a percentage of CP.
3) Discount % is a percentage of MP.

Example 5

A shopkeeper purchases a product at Rs. 800800, marks it up by 60%60 \% and then sells it at a discount of 25%25 \% to a customer. What is the shopkeeper's profit from this transaction?

Solution

Cost Price =800= 800 ; Mark-up %=60%\% = 60 \% ; Discount %=25%\% = 25 \%

Marked Price
=800×(1+60100)=1280= 800 \times \left(1 + \dfrac{60}{100} \right) = 1280

Selling Price
=1280×(125100)=960= 1280 \times \left(1 - \dfrac{25}{100} \right) = 960

Profit
=960800=160= 960 - 800 = 160

Answer: Rs.
160160

Example 6

If a seller marks up her goods by 45%45 \% and offers a discount of 30%30 \%, then what is her profit percentage?

Solution

As there are no values provided, we can assume CP =100= 100.

MP
=100×(1+45100)=145= 100 \times \left(1 + \dfrac{45}{100} \right) = 145

SP
=145×(130100)=101.5= 145 \times \left(1 - \dfrac{30}{100} \right) = 101.5

Profit
%=101.5100100×100\% = \dfrac{101.5 - 100}{100} \times 100% = \bm{1.5}%

Alternatively, as the base is
100100, Profit %=101.5100=1.5\% = 101.5 - 100 = \bm{1.5}%

Answer:
1.5%1.5 \%

Example 7

A trader marks up his goods by 40% and provides a discount of 20%20 \%. If he made an overall profit of Rs. 9090 by selling these goods, what was the selling price of the goods?

(1) Rs.
750750            (2) Rs. 840840            (3) Rs. 900900            (4) Rs. 10801080           

Solution

As an absolute value of Rs. 9090 is provided, we use a variable (and not assume a value).

Let CP
=x= x.

MP
=x(1+40100)=7x5= x\left(1 + \dfrac{40}{100} \right) = \dfrac{7x}{5}

SP
=7x5(120100)=7x5×45=28x25= \dfrac{7x}{5} \left(1 - \dfrac{20}{100} \right) = \dfrac{7x}{5} \times \dfrac{4}{5} = \dfrac{28x}{25}

As the profit
=90= 90,

SP - CP
=28x25x= \dfrac{28x}{25} - x = 9090

x⇒ x = 750750

SP
=28x25== \dfrac{28x}{25} = Rs. 840840

Answer: (2) Rs.
840840

Want to read the full content

Unlock this content & enjoy all the features of the platform

Subscribe Now arrow-right
videovideo-lock