Observation/Strategy
1) Compound interest also grows at the same rate as that of the interest rate.
2) For the next
3 years, the interest is higher by Rs. 5,000 because interest rate is being applied on the first 3 year's interest of Rs. 10,000.
Let r be the interest rate.
Interest for the first 3 years =Rs.10,000
Interest for the next 3 years =25,000−10,000=Rs.15,000.
From Point 2, we form the following equation.
10000×(1+100r)3=15000
⇒ (1+100r)3=1000015000=1.5
For a principal p, the interest at the end of 3 years is Rs. 10,000.
A=p(1+100r)n
⇒ p+10000=p×(1+100r)3
⇒ p+10000=p×1.5
⇒ 0.5p=10000
⇒ p=20000
Answer: (3) Rs. 20,000