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In the adjacent figure, r is the radius of the base. h is the height of the cone. l is the slant height of the cone, wherein l=r2+h2 Volume of cone =31πr2h Curved Surface Area (CSA) = πrl Flat Surface Area (FSA) = πr2 Total Surface Area (TSA) = πr(l+r) | ![]() |
In the adjacent figure, h is the height of the right pyramid. l is the slant height of the right pyramid. Volume of right pyramid =31× Area of base ×h Lateral Surface Area (LSA) = 21× Perimeter of base ×l Total Surface Area (TSA) = LSA + Area of Base | ![]() |
If a is the length of the side of the regular hexagon, Area of Hexagon = 6×43×a2 = 503 ⇒ a2 = 3100 ⇒ a ⇒ 310 |
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In the adjoining figure, the line connecting the mid point of the side of the hexagon to the centre, i.e. DO is perpendicular to the height OA. AD is perpendicular to the base in △ABC. ∴ We get a right angled triangle AOD. AO = Height of the pyramid = 12 m |
In the adjacent figure, r is the radius of the smaller circular top. R is the radius of the larger circular base. h is the height of the frustum l is the slant height of the frustum.wherein l=(R–r)2+h2 Volume of frustum=31πh×(R2+Rr+r2) Curved Surface Area (CSA) = πl(R+r) Flat Surface Area (FSA) = πR2+πr2 Total Surface Area (TSA) = π(lR+lr+R2+r2) | ![]() |
Let DE be the radius(r) of the frustum’s smaller circular top, BC be the radius(R) of larger circular base and AC be the slant height(l) of the frustum. Curved Surface Area of Frustum = π(r+R)l = 105π ⇒ π(r+12)5 = 105π ⇒ r + 12 = 21, r = 9 In △ABC and △ADE ∠ABC = ∠ADE (Right Angle) ∠BAC = ∠DAE (Common Angle) △ABC ~ △ADE(AA Rule) |
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