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Arithmetic II

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Mixtures & Alligations
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CAT 2025 Lesson : Mixtures & Alligations - Concepts & Cheatsheet

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Note: The video for this module contains a summary of all the concepts covered in this lesson. The video would serve as a good revision. Please watch this video in intervals of a few weeks so that you do not forget the concepts. Below is a cheatsheet that includes all the formulae but not necessarily the concepts covered in the video.

8. Cheatsheet

1)1) x4=x1w1+x2w2+...+xnwnw1+w2+...+wnx_{4} = \dfrac{x_{1}w_{1} + x_{2}w_{2} + ... + x_{n}w_{n}}{w_{1} + w_{2} + ... + w_{n}}.

2)2) w1w2=(x2xA)(xAx2)\dfrac{w_{1}}{w_{2}} = \dfrac{(x_{2} - x_{A})}{(x_{A} - x_{2})}



33) Where I\bm{I} is the initial quantity of non-replaced liquid,
r%\bm{r\%} is the replacement percentage,
n\bm{n} is the number of replacements,
F\bm{F} is the final quantity of the non-replaced liquid,

F=I×(1r100)nF = I \times \left(1 - \dfrac{r}{100} \right)^{n}

44) If the quantity replaced is provided (for example, in litres) instead of percentage,

F=I×(1Replacement QuantityTotal Quantity)nF = I \times \left(1 - \dfrac{\text{Replacement Quantity}}{\text{Total Quantity}} \right)^{n}

55) Where the quantities of 22 mixtures of different unknown concentrations are a\bm{a} and b\bm{b} , and a quantity of x\bm{x} is removed from each of the mixtures and placed in the other mixtures, and this results in both the mixtures having the same concentrations, then

x=aba+bx = \dfrac{ab}{a + b}
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