calendarBack
Quant

/

Numbers

/

Number Theory
ALL MODULES

CAT 2025 Lesson : Number Theory - Types of Numbers

bookmarked

2. Types of Numbers

All numbers can be divided into real and imaginary numbers. Real numbers are those which can be plotted on a number line.

Imaginary numbers are those which do not exist on a number line. These can be written as a real number multiplied by an imaginary unit
ii, where ii =1= \sqrt{-1}. A complex number is a number that can be expressed in the form a+bia + bi, where aa and bb are real numbers and ii is the imaginary unit. Complex and Imaginary numbers are not in the curriculum of most management entrance exams including CAT. Therefore, we will not be discussing this further.

2.1 Real Numbers

Real numbers are categorised as rational numbers and irrational numbers.

2.1.1 Rational numbers

Numbers that can be expressed in the form
pq\dfrac{p}{q}, where pp and qq are integers and q0q \ne 0, are called rational numbers. The following are examples of rational numbers.

5=515 = \dfrac{5}{1}      ;        1.25=125100=54-1.25 = \dfrac{-125}{100} = \dfrac{-5}{4}       ;       2.66666.....=2.6=832.66666..... = 2.\overline{6} = \dfrac{8}{3}           

1.428571428571...=1.428571=107-1.428571428571... = -1.\overline{428571} = \dfrac{-10}{7}

Rational numbers can be numbers with an infinite set of digits after the decimal point, as long as these digits are recurring. An
overline\overline{\text{overline}} is used to represent the recurring set of digit(s).

The following example shows how to convert a number with recurring digits after the decimal to the
pq\dfrac{p}{q} form.

Example 2

Express 0.5757570.575757... as a fraction.

Solution

Let x=0.57(1)x = 0.\overline{57} \longrightarrow (1)
100x=57.57(2)100x = 57.\overline{57} \longrightarrow (2)

(2)(1)(2) - (1)100xx=57.570.57 100x - x = 57.\overline{57} - 0.\overline{57}

99x=57 99x = 57x=5799 x = \dfrac{57}{99}

Answer:
5799\dfrac{57}{99}


Example 3

Let D be a recurring decimal of the form, D = 0.a1a2a1a2a1a2.......0.a_1a_2a_1a_2a_1a_2 ......., where digits a1a_1 and a2a_2 lie between 00 and 99. Further, at most one of them is zero. Then which of the following numbers necessarily produces an integer, when multiplied by D?
[CAT 2000]

(1)
1818            (2) 108108            (3) 198198            (4) 288288           

Solution

As exactly two digits are recurring,

D=0.a1a2(1) \mathrm{D} = 0.\overline{a_{1}a_{2}} \longrightarrow (1)

100D=a1a2.a1a2(2)100\mathrm{D} = a_{1}a_{2}.\overline{a_{1}a_{2}} \longrightarrow (2)

(2)(1(2) - (1) ⇒ 99D=a1a2 99\mathrm{D} = a_{1}a_{2}

D=a1a299 \mathrm{D} = \dfrac{a_{1}a_{2}}{99}

198198 is the only option which perfectly divides 9999.

198×D=2a1a2\therefore 198 \times \mathrm{D} = 2 a_{1}a_{2} is always an integer.

Answer: (3)
198198


If every three digits are recurring, then we multiply by
10310^3 and subtract. Therefore, if every nn digits are recurring, then we multiply by 10n10^n.

2.1.2 Irrational numbers

Numbers that cannot be expressed in the form
pq\dfrac{p}{q} are irrational numbers. The digits after the decimal place in these numbers will not be recurring. The following are examples of irrational numbers

π=3.14159265359...\pi = 3.14159265359... ;2=1.4142135624...\sqrt{2} = 1.4142135624... ; 313=1.4422495703...3^\frac{1}{3} = 1.4422495703...

Note that
227=3.142857\dfrac{22}{7} = 3.\overline{142857} is a close approximation of π\pi. Therefore, π=227\pi = \dfrac{22}{7} is used to approximate and simplify calculations in geometry. However, π\pi is an irrational number.

2.2 Other Terminologies

Following are some of the different types of real numbers.

Integers: All numbers that have
00 after the decimal point. Examples are 55 and 59-59.

Decimals: Numbers expressed with a denominator of
11. These are typically expressed with a decimal point. The digit placed to the immediate left of the decimal point is the units digit and that to the immediate right is the tenths digit. Integers are decimals as well. Examples are 4.044.04, 5.25-5.25, 1.55551.5555...

Fractions: Numbers expressed in the form
pq\dfrac{p}{q} , where pp and qq are integers and q0q \ne 0. Examples are 51\dfrac{5}{1}, 154\dfrac{-15}{4}, 46541\dfrac{465}{41}.

Natural numbers: This is the set of all positive integers. The sequence of natural numbers is
11, 22, 33, 44, ... There is an infinite number of natural numbers.

Whole numbers: This is the set of all non–negative integers. They include the number
00 and all the natural numbers. The sequence of whole numbers is 00, 11, 22, 33, ...

Even numbers: These are integral multiples of
22. These can be expressed in the form 2n2n, where nn is an integer. These numbers end with a units digit of either 00, 22, 44, 66 or 88. Examples are 36-36, 00, 1212 and 894734894734.

Odd numbers: These are integers that leave a remainder of
11 when divided by 22. These can be expressed in the form 2n+12n + 1, where nn is an integer. These numbers end with a units digit of either 1,3,5,71, 3, 5, 7 or 99. Examples are 4593-4593, 11, 1919 and 864207864207.

Arithmetic Properties of Odd and Even numbers:

Addition Multiplication
Even + Even == Even Even ×\times Even == Even
Even + Odd == Odd Even ×\times Odd == Even
Odd + Odd == Even Odd ×\times Odd == Odd


Example 4

If x=36+912+...90x = 3 - 6 + 9 - 12 + ... - 90, then which of the following is true?

(1)
xx is even but not divisible by 44
(2)
xx is divisible by 44
(3)
xx is odd
(4) None of the above

Solution

The terms are the first 3030 multiples of 33 with alternating signs (+(+ and )-).

∴ There are a total of
3030 terms.

Starting from the first term, if we group every
22 terms as a pair, we get 1515 terms

x=333....15 termsx = -3-3-3...._{\text{15 terms}}

x=3×15=45x = -3 \times 15 = -45

Answer: (3)
xx is odd

Example 5

Where xx and yy are integers, if x+yx + y is odd and xyxy is even, then which of the following is true?

(1)
x+xyx + xy is even     (2) x2+y2x^2 + y^2 is odd     (3) (x+y)2(x + y)^2 is even     (4) 5xy5xy is odd

Solution

As x+yx + y is odd and xyxy is even, one of x\bm{x } or y\bm{y} is odd, while the other is even.

Option 1: We do not know if
xx is even or not. \therefore Inconclusive

Option 2:
a2a^2 would remain odd if aa is odd and remain even if aa is even. ∴ x2+y2x^2 + y^2 is odd, as it is the sum of 1 odd and 1 even number. True

Option 3: As
x+yx + y is odd, (x+y)2(x + y)^2 will also be odd. False

Option 4: As
xyxy is even, 5xy5xy is also even. False

Answer: (2)
x2+y2x^2 + y^2 is odd

Want to read the full content

Unlock this content & enjoy all the features of the platform

Subscribe Now arrow-right
videovideo-lock