calendarBack
Quant

/

Arithmetic I

/

Percentages
ALL MODULES

CAT 2025 Lesson : Percentages - To & By and Multiplication Factor

bookmarked

4.4 Increase/Decrease to vs by

Where
xx and yy are two numbers,
- if
xx has increased or decreased to yy, then xx has become yy.
- if
xx has increased by yy, then xx has become x+yx + y.
- if
xx has decreased by yy, then xx has become xyx - y.

The same applies for percentages. For instance,

If
xx has increased to 150%, then xx has become (150100)×x=1.5x\left( \dfrac{150}{100} \right) \times x = 1.5x

If
xx has increased by 150%, then xx has become (1+150100)×x=2.5x\left( 1 + \dfrac{150}{100} \right) \times x = 2.5x

Example 10

In a fraction, the numerator is increased by 120%120\% while the denominator is increased to 160%160\%, the resulting fraction is 12\dfrac{1}{2}. Which of the following is the fraction?

(1)
822\dfrac{8}{22}            (2) 1322\dfrac{13}{22}            (3) 56\dfrac{5}{6}            (4) 23\dfrac{2}{3}           

Solution

Note that the numerator increases by 120%120\%, while denominator increases to 160%160\%.

Let the number be
xy\dfrac{x}{y}.

2.2x1.6y=12\therefore \dfrac{2.2 x}{1.6 y} = \dfrac{1}{2}

xy=411=822 \dfrac{x}{y} = \dfrac{4}{11} = \dfrac{8}{22}

Answer: (1)
822\dfrac{8}{22}

Example 11

Population of a village increased by 60%60\% in 20012001, reduced to 75%75\% in 20022002, increased to 150%150\% in 20032003. If the population at the end of 20032003 was 5454 crores, then what was the population of the village in 20002000?

Solution

Note that by and to have been used for different years.

Let the population at the beginning of 20002000 be xx.

x×1.6×0.75×1.5=54x \times 1.6 \times 0.75 \times 1.5 = 54

These decimals can easily be expressed as fractions, which would ease the calculation.

x×85×34×32=54 x \times \dfrac{8}{5} \times \dfrac{3}{4} \times \dfrac{3}{2} = 54

x×95=54 \dfrac{x \times 9}{5} = 54

x=30 x = 30

Answer:
3030 crores

4.5 Multiplication Factor

Applying multiplication factors for percentage increase and decrease improves the solving speed. Good knowledge of 3.0 Common Fractions as Decimal & Percentage will further improve your speed.

If a certain value is increased by
x%x\% or decreased by y%y\%, then (1+x100)\left( 1 + \dfrac{x}{100} \right) or (1y100)\left( 1 - \dfrac{y}{100} \right) are the respective multiplying factors.

Let's say
120120 is to be reduced by 30%30\%. Applying the multiplication factor, we get

120×(130100)=120×710=84120 \times \left( 1 - \dfrac{30}{100} \right) = 120 \times \dfrac{7}{10} = 84

710\dfrac{7}{10} or 0.70.7 is considered the multiplying factor here. This can be expressed as a fraction or decimal.

Example 12

Cicero had only two forms of expenses - rent and food. In 20202020, food expense accounted for 60%60\% of his total expense. In 20212021, if his rent expense increased by 25%25\% and food expense reduced by 20%20\%, then what was the percentage change in his total annual expense

Solution

Note that absolute values (in rupees) is not provided and we are required to find the percentage change. So, we can assume values. Using 100 or multiples of 100 makes calculations easier.

Secondly, we have 2 time periods (2020 and 2021) and the same type of expenses (rent and food).
Therefore, we can use a table to fill details. This improves the speed in solving, as well.

Let the expense in 2020 be Rs. 100.
∴ Food expense in 2020 is 60% of Rs. 100 = Rs. 60
Rent expense in 2020 = 100 – 60 = Rs. 40

Expense 2020 2021
Rent 40
Food 60
Total 100

Rent expense in 2021 = (1+25100)×40=54×40\left( 1 + \dfrac{25}{100} \right) \times 40 = \dfrac{5}{4} \times 40 = Rs. 50

Food expense in 2021 =
(120100)×60=45×60\left( 1 - \dfrac{20}{100} \right) \times 60 = \dfrac{4}{5} \times 60 = Rs. 48

Expense 2020 2021
Rent 40 50
Food 60 48
Total 100 98

As expense has reduced from Rs.
100100 to Rs. 9898, there has been a decrease of 2%2\% in the total annual expense.

Answer: 2%

4.6 Percentage Change

If
pp has been changed to qq, percentage change = qpp×100%\dfrac{q - p}{p} \times 100\%

If
q>pq \gt p, then the change is positive, meaning an increase.
If
q<pq \lt p, then the change is negative, meaning a decrease.

Example 13

Kamla's height was 44 feet 22 inches last month. If she is 4.54.5 feet now, calculate the percentage increase in her height?

Solution

11 foot = 1212 inches

44 feet 22 inches = 48+2=5048 + 2 = 50 inches

4.54.5 feet = 4.5×12=544.5 \times 12 = 54 inches

Change in height =
545050×\dfrac{54 - 50}{50} \times 100% = 8%

Answer:
8%8\%

To increase a number by
r%r\%, multiply the number by (1+r100)\left( 1 + \dfrac{r}{100} \right)

To decrease a number by
r%r\%, multiply the number by (1r100)\left( 1 - \dfrac{r}{100} \right)

Example 14

Time taken to travel from Mecca to Medina used to be 88 hours. Due to improved roads, the time taken has reduced by 37.5%37.5\%. Calculate the current travel time.

Solution

r=37.5%=38r = 37.5\% = \dfrac{3}{8}

Current time taken
=8×(138)=8×58=5= 8 \times \left( 1 - \dfrac{3}{8} \right) = 8 \times \dfrac{5}{8} = 5 hours

Answer:
55 hours

Want to read the full content

Unlock this content & enjoy all the features of the platform

Subscribe Now arrow-right
videovideo-lock