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Arithmetic I

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Percentages

Percentages

MODULES

Basics of Percentages
Fractions to Memorise
Of Concept & The Denominator
To & By and Multiplication Factor
Successive Changes & %age Points
Product Constancy
Index & Inflation
Common Types
Past Questions

CONCEPTS & CHEATSHEET

Concept Revision Video

SPEED CONCEPTS

Percentages 1
-/10
Percentages 2
-/10
Percentages 3
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PRACTICE

Percentages : Level 1
Percentages : Level 2
Percentages : Level 3
ALL MODULES

CAT 2025 Lesson : Percentages - To & By and Multiplication Factor

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4.4 Increase/Decrease to vs by

Where
xxx and yyy are two numbers,
- if
xxx has increased or decreased to yyy, then xxx has become yyy.
- if
xxx has increased by yyy, then xxx has become x+yx + yx+y.
- if
xxx has decreased by yyy, then xxx has become x−yx - yx−y.

The same applies for percentages. For instance,

If
xxx has increased to 150%, then xxx has become (150100)×x=1.5x\left( \dfrac{150}{100} \right) \times x = 1.5x(100150​)×x=1.5x

If
xxx has increased by 150%, then xxx has become (1+150100)×x=2.5x\left( 1 + \dfrac{150}{100} \right) \times x = 2.5x(1+100150​)×x=2.5x

Example 10

In a fraction, the numerator is increased by 120%120\%120% while the denominator is increased to 160%160\%160%, the resulting fraction is 12\dfrac{1}{2}21​. Which of the following is the fraction?

(1)
822\dfrac{8}{22}228​            (2) 1322\dfrac{13}{22}2213​            (3) 56\dfrac{5}{6}65​            (4) 23\dfrac{2}{3}32​           

Solution

Note that the numerator increases by 120%120\%120%, while denominator increases to 160%160\%160%.

Let the number be
xy\dfrac{x}{y}yx​.

∴2.2x1.6y=12\therefore \dfrac{2.2 x}{1.6 y} = \dfrac{1}{2}∴1.6y2.2x​=21​

⇒
xy=411=822 \dfrac{x}{y} = \dfrac{4}{11} = \dfrac{8}{22}yx​=114​=228​

Answer: (1)
822\dfrac{8}{22}228​

Example 11

Population of a village increased by 60%60\%60% in 200120012001, reduced to 75%75\%75% in 200220022002, increased to 150%150\%150% in 200320032003. If the population at the end of 200320032003 was 545454 crores, then what was the population of the village in 200020002000?

Solution

Note that by and to have been used for different years.

Let the population at the beginning of 200020002000 be xxx.

x×1.6×0.75×1.5=54x \times 1.6 \times 0.75 \times 1.5 = 54x×1.6×0.75×1.5=54

These decimals can easily be expressed as fractions, which would ease the calculation.

⇒
x×85×34×32=54 x \times \dfrac{8}{5} \times \dfrac{3}{4} \times \dfrac{3}{2} = 54x×58​×43​×23​=54

⇒
x×95=54 \dfrac{x \times 9}{5} = 545x×9​=54

⇒
x=30 x = 30x=30

Answer:
303030 crores

4.5 Multiplication Factor

Applying multiplication factors for percentage increase and decrease improves the solving speed. Good knowledge of 3.0 Common Fractions as Decimal & Percentage will further improve your speed.

If a certain value is increased by
x%x\%x% or decreased by y%y\%y%, then (1+x100)\left( 1 + \dfrac{x}{100} \right)(1+100x​) or (1−y100)\left( 1 - \dfrac{y}{100} \right)(1−100y​) are the respective multiplying factors.

Let's say
120120120 is to be reduced by 30%30\%30%. Applying the multiplication factor, we get

120×(1−30100)=120×710=84120 \times \left( 1 - \dfrac{30}{100} \right) = 120 \times \dfrac{7}{10} = 84120×(1−10030​)=120×107​=84

710\dfrac{7}{10}107​ or 0.70.70.7 is considered the multiplying factor here. This can be expressed as a fraction or decimal.

Example 12

Cicero had only two forms of expenses - rent and food. In 202020202020, food expense accounted for 60%60\%60% of his total expense. In 202120212021, if his rent expense increased by 25%25\%25% and food expense reduced by 20%20\%20%, then what was the percentage change in his total annual expense

Solution

Note that absolute values (in rupees) is not provided and we are required to find the percentage change. So, we can assume values. Using 100 or multiples of 100 makes calculations easier.

Secondly, we have 2 time periods (2020 and 2021) and the same type of expenses (rent and food).
Therefore, we can use a table to fill details. This improves the speed in solving, as well.

Let the expense in 2020 be Rs. 100.
∴ Food expense in 2020 is 60% of Rs. 100 = Rs. 60
Rent expense in 2020 = 100 – 60 = Rs. 40

Expense 2020 2021
Rent 40
Food 60
Total 100

Rent expense in 2021 = (1+25100)×40=54×40\left( 1 + \dfrac{25}{100} \right) \times 40 = \dfrac{5}{4} \times 40(1+10025​)×40=45​×40 = Rs. 50

Food expense in 2021 =
(1−20100)×60=45×60\left( 1 - \dfrac{20}{100} \right) \times 60 = \dfrac{4}{5} \times 60(1−10020​)×60=54​×60 = Rs. 48

Expense 2020 2021
Rent 40 50
Food 60 48
Total 100 98

As expense has reduced from Rs.
100100100 to Rs. 989898, there has been a decrease of 2%2\%2% in the total annual expense.

Answer: 2%

4.6 Percentage Change

If
ppp has been changed to qqq, percentage change = q−pp×100%\dfrac{q - p}{p} \times 100\%pq−p​×100%

If
q>pq \gt pq>p, then the change is positive, meaning an increase.
If
q<pq \lt pq<p, then the change is negative, meaning a decrease.

Example 13

Kamla's height was 444 feet 222 inches last month. If she is 4.54.54.5 feet now, calculate the percentage increase in her height?

Solution

111 foot = 121212 inches

444 feet 222 inches = 48+2=5048 + 2 = 5048+2=50 inches

4.54.54.5 feet = 4.5×12=544.5 \times 12 = 544.5×12=54 inches

Change in height =
54−5050×\dfrac{54 - 50}{50} \times5054−50​× 100% = 8%

Answer:
8%8\%8%

To increase a number by
r%r\%r%, multiply the number by (1+r100)\left( 1 + \dfrac{r}{100} \right)(1+100r​)

To decrease a number by
r%r\%r%, multiply the number by (1−r100)\left( 1 - \dfrac{r}{100} \right)(1−100r​)

Example 14

Time taken to travel from Mecca to Medina used to be 888 hours. Due to improved roads, the time taken has reduced by 37.5%37.5\%37.5%. Calculate the current travel time.

Solution

r=37.5%=38r = 37.5\% = \dfrac{3}{8}r=37.5%=83​

Current time taken
=8×(1−38)=8×58=5= 8 \times \left( 1 - \dfrac{3}{8} \right) = 8 \times \dfrac{5}{8} = 5=8×(1−83​)=8×85​=5 hours

Answer:
555 hours

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