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Probability

Probability

MODULES

Basics of Probability
Mutually Exclusive Events
Non-Mutually Exclusive Events
Independent Events
Dependent Events
Conditional Probability
Odds For & Against
Past Questions

CONCEPTS & CHEATSHEET

Concept Revision Video

SPEED CONCEPTS

Probability 1
-/10
Probability 2
-/10

PRACTICE

Probability : Level 1
Probability : Level 2
Probability : Level 3
ALL MODULES

CAT 2025 Lesson : Probability - Concepts & Cheatsheet

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Note: The video for this module contains a summary of all the concepts covered in this lesson. The video would serve as a good revision. Please watch this video in intervals of a few weeks so that you do not forget the concepts. Below is a cheatsheet that includes all the formulae but not necessarily the concepts covered in the video.

   9. Cheatsheet

111) P(E) = Number of favorable outcomesTotal possible outcomes\dfrac{\text{Number of favorable outcomes}}{\text{Total possible outcomes}}Total possible outcomesNumber of favorable outcomes​ = n(E)n(S)\dfrac{n\text{(E)}}{n\text{(S)}}n(S)n(E)​

222) Basic Properties
(a)
0≤0 \leq0≤ P(E) ≤1\leq 1≤1
(b) P
(E‾)(\overline{\text{E}})(E) =1−= 1 -=1− P(E)
(c) P(A
∪\cup∪ B) === P(A) +++ P(B) −-− P(A ∩\cap∩ B)

333) Mutually exclusive events are those where only one of them can occur at a time, i.e., P(A ∩\cap∩ B) =0= \bm{0}=0

444) Non-mutually exclusive events are those where more than 111 event can occur at a time, i.e. P(A ∩\cap∩ B) ≠\ne= 0\bm{0}0

555) Probability of occurrence of two independent events (A and B) is P(A and B) = P(A) ×\times × P(B)
Probability of both A and B not occurring is P(
A‾\overline{\text{A}}A and B‾\overline{\text{B}}B) === (1−1 -1− P(A)) ×\times× (1−1 -1− P(B))

666) Independent Events with 2\bm{2}2 outcomes: P(A occurring r times out of a total nnn )
=== nCr^{n}C_{r}nCr​[P(A)]r^{r}r[P(B)]n−r^{n - r}n−r

777) Dependent Events: P(A and B and C and ...) === P(A) ×\times× P(B given A) ×\times× P(C given A and B) ×\times× ...

888) P(A / B) is the Conditional Probability of an event A occurring given that an event B has already occurred.

P(A / B)
=P(A∩B)P(B)== \dfrac{\text{P}(\text{A} \cap \text{B})}{\text{P}(\text{B})} ==P(B)P(A∩B)​= n(A∩B)n(B)\dfrac{n (\text{A} \cap \text{B})}{n(\text{B})}n(B)n(A∩B)​

999) Odds for an event is the ratio of favourable to unfavourable cases.

Odds against an event is the ratio of unfavourable to favourable cases.

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