+91 9600 121 800

Plans

Dashboard

Daily & Speed

Quant

Verbal

DILR

Compete

Free Stuff

calendarBack
Quant

/

Modern Maths

/

Progressions

Progressions

MODULES

bookmarked
AP Concepts
bookmarked
AP Examples
bookmarked
AP Special Types
bookmarked
GP Concepts
bookmarked
GP Special Types
bookmarked
HP Concepts
bookmarked
Special Types I
bookmarked
Special Types II
bookmarked
Past Questions

CONCEPTS & CHEATSHEET

Concept Revision Video

SPEED CONCEPTS

Progressions 1
-/10
Progressions 2
-/10

PRACTICE

Progressions : Level 1
Progressions : Level 2
Progressions : Level 3
ALL MODULES

CAT 2025 Lesson : Progressions - AP Concepts

bookmarked

1. Introduction

Sequence is a set of numbers that follow a logical rule or pattern. This logical rule/pattern need not necessarily translate into a formula.

Progression is a set of numbers that follow a logical rule, which has a formula to calculate the
nth n^{\text{th}} nth term. This lesson will cover the different forms of progressions that we are tested on with special focus on the 333 basic forms of progressions – Arithmetic Progression (AP), Geometric Progression (GP), and Harmonic Progression (HP).

Terms Pattern nth term Sequence? Progression?
555, 888, 111111, 141414, 171717 , ... Difference between consecutive terms is 333. 5+3×(n−1)5 + 3 \times (n - 1) 5+3×(n−1) Yes Yes
27,9,3,1,27, 9, 3, 1,27,9,3,1, 13 \dfrac{1}{3} 31​, 19 \dfrac{1}{9} 91​, ... Every consecutive term is a multiple of (13\dfrac{1}{3}31​) . 27×27 \times27× ( 13)(n−1)\dfrac{1}{3} )^{(n - 1)}31​)(n−1) Yes Yes
2,3,5,7,11,13,17 2, 3, 5, 7, 11, 13, 172,3,5,7,11,13,17, ... List of all prime numbers. No direct formula Yes No
1,1,2,3,5,8,13,..1, 1, 2, 3, 5, 8, 13, ..1,1,2,3,5,8,13,... Sum of previous 222 numbers. No direct formula Yes No


2. Arithmetic Progression

If the difference between every two consecutive terms of a sequence is constant, then the sequence is said to be in Arithmetic Progression (AP).

If
x1,x2,x3,x4,...,xn x_1, x_2, x_3, x_4, ..., x_n x1​,x2​,x3​,x4​,...,xn​ are in Arithmetic Progression, then x2−x1=x3−x2=...=xn−xn−1 x_2 - x_1 = x_3 - x_2 = ... = x_n - x_{n - 1} x2​−x1​=x3​−x2​=...=xn​−xn−1​

Where
aaa is the first term and ddd is the common difference, the terms of the AP will be

aaa, a+da + da+d, a+2da + 2da+2d, a+3da + 3da+3d, ... , aaa + (nnn - 1)ddd

∴
x1=ax_1 = ax1​=a
x2=a+dx_2 = a + dx2​=a+d
x3=a+2dx_3 = a + 2dx3​=a+2d
x4=a+3dx_4 = a + 3dx4​=a+3d
xnx_n xn​ === aaa + (nnn – 1)ddd

For the following examples of AP, not the first term
(a) (a) (a) and common difference (d) (d) (d).

Arithmetic Progression a & d nth^{\text{th}}th term
333, 777, 111111, ... a=3a = 3a=3, d=4d = 4d=4 3+(n−1)×43+(n-1) \times 43+(n−1)×4
−89-89−89, −72-72−72, −55-55−55, ... aaa =−89= -89=−89, d=17d = 17d=17 −89+(n−1)×17-89+(n-1) \times 17−89+(n−1)×17
100100100, 969696, 929292, ... a=100a = 100a=100, ddd =−4= -4=−4 100+(n−1)×(−4)100+(n-1) \times (-4)100+(n−1)×(−4)


2.1 Terms & Formulae for AP

Where
aaa and ddd are the first term and common difference respectively in an AP with nnn terms,

1)
nth n^{\text{th}} nth === aaa + (nnn – 1)ddd

2) Average of an AP
=== Average of First and Last terms === x1+xn2\dfrac {x_1+x_n}{2}2x1​+xn​​

3) Sum of terms of an AP
=== Sn \bold{S_n} Sn​ === n×Average=n×(x1+xn2)=n2×[2a+(n−1)d]n \times \text{Average} = n \times \left( \dfrac{x_1 + x_n}{2} \right) = \dfrac {n}{2} \times [ 2a + (n-1)d ]n×Average=n×(2x1​+xn​​)=2n​×[2a+(n−1)d]

4) Number of terms in an AP
=== n n n === Last Term - First TermCommon Difference+1=xn−x1d+1\dfrac {\text{Last Term - First Term}}{\text{Common Difference}}+1 = \dfrac {x_n- x_1}{d}+1Common DifferenceLast Term - First Term​+1=dxn​−x1​​+1

2.2 Properties of AP

1) If each term of an AP is added, subtracted, multiplied or divided by a constant, then the resulting sequence is also in AP.

2) In two APs with the same number of terms, if the corresponding terms by position in the two APs are added/subtracted, the resulting sequence will also be in AP.

3) Average of an AP is its median.

4) If
a a a, bbb and cc c are in AP, then b=a+c2 b = \dfrac{a+c}{2}b=2a+c​

5) Sum of the first and last terms equals the second and second last terms, which then equals the third and third from last terms and so on (as shown below).

x1+xnx_1 + x_nx1​+xn​ === aaa + aaa + (nnn – 1)ddd === 2a2a2a + (nnn – 1)ddd
x2+xn−1x_2 + x_{n-1}x2​+xn−1​ === aaa + dd d+ aaa + (nnn – 2)dd d === 2a2a2a + (nnn – 1)ddd
x3+xn−2x_3 + x_{n-2} x3​+xn−2​ === aaa + 2d2d2d + aaa + (nnn – 3)ddd === 2a2a2a + (nnn – 1)ddd

Loading...Loading Video....