4. Areas with Symmetrical Shapes
In these questions we will be required to find the area of a shaded region when the overall area is given. Or, we might be required to find the ratio of the area of shaded region to that of the unshaded region, etc. We look for patterns in these shapes or divide them into symmetrical parts.
Example 22
In the following diagram, ABCD is a rectangle where E and F are the mid-points of AD and BC respectively. What percentage of the rectangle is shaded?
Solution
We mark G and F – the mid-points of AB and CD respectively.
When we join BD and GH, we get 8 congruent triangles.
Of these 8 triangles, only 2 of them are shaded.
∴ Portion of shaded area =82×100%=25%.
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Answer:
25%
Example 23
In the below figure, H, E, D, F and G are the mid-points of BC, AC, AB, BD and EC respectively. What is the ratio of the shaded region to the unshaded region?
Solution
The parallelograms DEOF and FOBH are congruent.
∴ If we move the shaded region from DEOF to FOBH, we get the figure on the right.
∠A is common and ABAF=ACAG=43
∴ By SAS similarity rule, △AFG ∼ △ABC
△ABC△AFG=AB2AF2=169
Area of shaded region to that of △ABC = 1 −169=167
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Ratio of areas of shaded to unshaded = 7 : 9
Answer:
7:9
Example 24
ABCD is a rectangle. P and Q are points on CD such that DP = PQ = QC. O is a point on AB. What is the ratio of the shaded region to that of ABCD?
Solution
Area of rectangle ABCD =length×breadth=3xy
In △ OPQ, the altitude to base PQ will be of the same length as AD, i.e., y.
Area of △OPQ =21×y×x=2xy
Ratio of △OPQ to ABCD =2xy:3xy=1:6 |
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Answer:
1:6