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We mark G and F – the mid-points of AB and CD respectively. When we join BD and GH, we get 8 congruent triangles. Of these 8 triangles, only 2 of them are shaded. ∴ Portion of shaded area =82×100%=25%. |
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The parallelograms DEOF and FOBH are congruent. ∴ If we move the shaded region from DEOF to FOBH, we get the figure on the right. ∠A is common and ABAF=ACAG=43 ∴ By SAS similarity rule, △AFG ∼ △ABC △ABC△AFG=AB2AF2=169 Area of shaded region to that of △ABC = 1 −169=167 |
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Area of rectangle ABCD =length×breadth=3xy In △ OPQ, the altitude to base PQ will be of the same length as AD, i.e., y. Area of △OPQ =21×y×x=2xy Ratio of △OPQ to ABCD =2xy:3xy=1:6 |
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