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Number Theory

Number Theory

MODULES

Basics of Numbers
Types of Numbers
Fractions
Arithmetic Operations
Other Numerical Operations
Algebraic Expansion
Prime Numbers
Counting Integers
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ALL MODULES

CAT 2025 Lesson : Number Theory - Types of Numbers

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2. Types of Numbers

All numbers can be divided into real and imaginary numbers. Real numbers are those which can be plotted on a number line.

Imaginary numbers are those which do not exist on a number line. These can be written as a real number multiplied by an imaginary unit
iii, where iii =−1= \sqrt{-1}=−1​. A complex number is a number that can be expressed in the form a+bia + bia+bi, where aaa and bbb are real numbers and iii is the imaginary unit. Complex and Imaginary numbers are not in the curriculum of most management entrance exams including CAT. Therefore, we will not be discussing this further.

2.1 Real Numbers

Real numbers are categorised as rational numbers and irrational numbers.

2.1.1 Rational numbers

Numbers that can be expressed in the form
pq\dfrac{p}{q}qp​, where ppp and qqq are integers and q≠0q \ne 0q=0, are called rational numbers. The following are examples of rational numbers.

5=515 = \dfrac{5}{1}5=15​      ;        −1.25=−125100=−54-1.25 = \dfrac{-125}{100} = \dfrac{-5}{4}−1.25=100−125​=4−5​       ;       2.66666.....=2.6‾=832.66666..... = 2.\overline{6} = \dfrac{8}{3}2.66666.....=2.6=38​           

−1.428571428571...=−1.428571‾=−107-1.428571428571... = -1.\overline{428571} = \dfrac{-10}{7}−1.428571428571...=−1.428571=7−10​

Rational numbers can be numbers with an infinite set of digits after the decimal point, as long as these digits are recurring. An
overline‾\overline{\text{overline}}overline is used to represent the recurring set of digit(s).

The following example shows how to convert a number with recurring digits after the decimal to the
pq\dfrac{p}{q}qp​ form.

Example 2

Express 0.5757570.5757570.575757... as a fraction.

Solution

Let x=0.57‾⟶(1)x = 0.\overline{57} \longrightarrow (1)x=0.57⟶(1)
100x=57.57‾⟶(2)100x = 57.\overline{57} \longrightarrow (2)100x=57.57⟶(2)

(2)−(1)(2) - (1)(2)−(1) ⇒ 100x−x=57.57‾−0.57‾ 100x - x = 57.\overline{57} - 0.\overline{57}100x−x=57.57−0.57

⇒
99x=57 99x = 5799x=57 ⇒ x=5799 x = \dfrac{57}{99}x=9957​

Answer:
5799\dfrac{57}{99}9957​


Example 3

Let D be a recurring decimal of the form, D = 0.a1a2a1a2a1a2.......0.a_1a_2a_1a_2a_1a_2 .......0.a1​a2​a1​a2​a1​a2​......., where digits a1a_1a1​ and a2a_2a2​ lie between 000 and 999. Further, at most one of them is zero. Then which of the following numbers necessarily produces an integer, when multiplied by D?
[CAT 2000]

(1)
181818            (2) 108108108            (3) 198198198            (4) 288288288           

Solution

As exactly two digits are recurring,

D=0.a1a2‾⟶(1) \mathrm{D} = 0.\overline{a_{1}a_{2}} \longrightarrow (1)D=0.a1​a2​​⟶(1)

100D=a1a2.a1a2‾⟶(2)100\mathrm{D} = a_{1}a_{2}.\overline{a_{1}a_{2}} \longrightarrow (2)100D=a1​a2​.a1​a2​​⟶(2)

(2)−(1(2) - (1(2)−(1) ⇒ 99D=a1a2 99\mathrm{D} = a_{1}a_{2}99D=a1​a2​

⇒
D=a1a299 \mathrm{D} = \dfrac{a_{1}a_{2}}{99}D=99a1​a2​​

198198198 is the only option which perfectly divides 999999.

∴198×D=2a1a2\therefore 198 \times \mathrm{D} = 2 a_{1}a_{2}∴198×D=2a1​a2​ is always an integer.

Answer: (3)
198198198


If every three digits are recurring, then we multiply by
10310^3103 and subtract. Therefore, if every nnn digits are recurring, then we multiply by 10n10^n10n.

2.1.2 Irrational numbers

Numbers that cannot be expressed in the form
pq\dfrac{p}{q}qp​ are irrational numbers. The digits after the decimal place in these numbers will not be recurring. The following are examples of irrational numbers

π=3.14159265359...\pi = 3.14159265359... π=3.14159265359... ;2=1.4142135624...\sqrt{2} = 1.4142135624...2​=1.4142135624... ; 313=1.4422495703...3^\frac{1}{3} = 1.4422495703...331​=1.4422495703...

Note that
227=3.142857‾\dfrac{22}{7} = 3.\overline{142857}722​=3.142857 is a close approximation of π\piπ. Therefore, π=227\pi = \dfrac{22}{7}π=722​ is used to approximate and simplify calculations in geometry. However, π\piπ is an irrational number.

2.2 Other Terminologies

Following are some of the different types of real numbers.

Integers: All numbers that have
000 after the decimal point. Examples are 555 and −59-59−59.

Decimals: Numbers expressed with a denominator of
111. These are typically expressed with a decimal point. The digit placed to the immediate left of the decimal point is the units digit and that to the immediate right is the tenths digit. Integers are decimals as well. Examples are 4.044.044.04, −5.25-5.25−5.25, 1.55551.55551.5555...

Fractions: Numbers expressed in the form
pq\dfrac{p}{q}qp​ , where ppp and qqq are integers and q≠0q \ne 0q=0. Examples are 51\dfrac{5}{1}15​, −154\dfrac{-15}{4}4−15​, 46541\dfrac{465}{41}41465​.

Natural numbers: This is the set of all positive integers. The sequence of natural numbers is
111, 222, 333, 444, ... There is an infinite number of natural numbers.

Whole numbers: This is the set of all non–negative integers. They include the number
000 and all the natural numbers. The sequence of whole numbers is 000, 111, 222, 333, ...

Even numbers: These are integral multiples of
222. These can be expressed in the form 2n2n2n, where nnn is an integer. These numbers end with a units digit of either 000, 222, 444, 666 or 888. Examples are −36-36−36, 000, 121212 and 894734894734894734.

Odd numbers: These are integers that leave a remainder of
111 when divided by 222. These can be expressed in the form 2n+12n + 12n+1, where nnn is an integer. These numbers end with a units digit of either 1,3,5,71, 3, 5, 71,3,5,7 or 999. Examples are −4593-4593−4593, 111, 191919 and 864207864207864207.

Arithmetic Properties of Odd and Even numbers:

Addition Multiplication
Even + Even === Even Even ×\times× Even === Even
Even + Odd === Odd Even ×\times× Odd === Even
Odd + Odd === Even Odd ×\times× Odd === Odd


Example 4

If x=3−6+9−12+...−90x = 3 - 6 + 9 - 12 + ... - 90x=3−6+9−12+...−90, then which of the following is true?

(1)
xxx is even but not divisible by 444
(2)
xxx is divisible by 444
(3)
xxx is odd
(4) None of the above

Solution

The terms are the first 303030 multiples of 333 with alternating signs (+(+(+ and −)-)−).

∴ There are a total of
303030 terms.

Starting from the first term, if we group every
222 terms as a pair, we get 151515 terms

x=−3−3−3....15 termsx = -3-3-3...._{\text{15 terms}}x=−3−3−3....15 terms​

x=−3×15=−45x = -3 \times 15 = -45x=−3×15=−45

Answer: (3)
xxx is odd

Example 5

Where xxx and yyy are integers, if x+yx + yx+y is odd and xyxyxy is even, then which of the following is true?

(1)
x+xyx + xyx+xy is even     (2) x2+y2x^2 + y^2x2+y2 is odd     (3) (x+y)2(x + y)^2(x+y)2 is even     (4) 5xy5xy5xy is odd

Solution

As x+yx + yx+y is odd and xyxyxy is even, one of x\bm{x }x or y\bm{y}y is odd, while the other is even.

Option 1: We do not know if
xxx is even or not. ∴\therefore∴ Inconclusive

Option 2:
a2a^2a2 would remain odd if aaa is odd and remain even if aaa is even. ∴ x2+y2x^2 + y^2x2+y2 is odd, as it is the sum of 1 odd and 1 even number. True

Option 3: As
x+yx + yx+y is odd, (x+y)2(x + y)^2(x+y)2 will also be odd. False

Option 4: As
xyxyxy is even, 5xy5xy5xy is also even. False

Answer: (2)
x2+y2x^2 + y^2x2+y2 is odd

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